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| | Rewrite Your Code Tomorrow One of the things that many developers learn over time is that they write better code with practice. In fact, some of the time a developer will find that if they write a bit of code to solve a problem, they'll come up with a better solution a day or two later, as they've had a chance to think about the problem. Even while moving on to other code, their brain will continue to examine the previous solution, inherently knowing the approach wasn't the best. Many of us see this with our code over time. If we look back at something we wrote a year or two ago, many of us cringe. At least, most of us cringe, especially if we constantly look to improve our skills. We see that old code as poorly written, in a way that we might never want to repeat in our career. I think that's a good sign that we are moving forward and learning better patterns over time. If you don't view any of your old code as poorly written, I'd stop and get a second opinion. You certainly might have written some great routines that stand the test of time, but more often than not, I find places where I'd improve code. Having someone else review my work might help me build better skills. One of the things I heard recommended recently was that developers solve some problem, commit the code in their VCS, and then tomorrow, redo the work. Start the day by deleting that section of code (that proc, method, class, etc.). Then move forward and rewrite the solution, not trying to remember what was there, but by resolving the issue. Plenty of application developers find they'll write similar logic, but better structured code. Even if you don't believe this, conduct an experiment on a small section of your code. I don't know if we'd come up with the same results with T-SQL as many of us tend to solve the problems the same way across a short period of time. However, maybe you'd like to post a mock up of your challenge and solution, and ask for some opinions. We have great forums at SQLServerCentral and some really sharp SQL developers. You might get the validation that you built a great solution, or maybe you'd get some ideas on how to improve both your code and your skills. Steve Jones from SQLServerCentral.comJoin the debate, and respond to today's editorial on the forums |
| The Voice of the DBA Podcast Listen to the MP3 Audio ( 3.1MB) podcast or subscribe to the feed at iTunes and Libsyn. The Voice of the DBA podcast features music by Everyday Jones. No relation, but I stumbled on to them and really like the music. | |
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| | | Press Release from Redgate When a SQL Server database is operating smoothly and performing well, there is no need to be particularly aware of the transaction log, beyond ensuring that every database has an appropriate backup regime and restore plan in place. When things go wrong, however, a DBA's reputation depends on a deeper understanding of the transaction log, both what it does, and how it works. More » |
| Additional Articles from Database Journal Azure Data Factory is a cloud based data integration service. This helps you to define, schedule and manage data pipelines to transfer and transform the data from disparate on premise and cloud data sources. Read on to learn more. More » |
| This article offers a brief, step-by-step guide to provisioning databases from a backup using SQL Clone. More » |
| iainthepitman from SQLServerCentral Blogs Introduction Policy Based Management (PBM) can be used to inform DBAs when an incorrect setting is being used on a SQL... More » |
| Cláudio Silva from SQLServerCentral Blogs Before I complete my question let me provide context. I’ve received an alert saying that a specific database could not allocate... More » |
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| | Today's Question (by Steve Jones): I want to store Marvel data. My goal is to store a character name, a movie title, and a year of release. Which construct in R creates a data frame? I have already set some variables: > characters <- c('Iron Man', 'Iron Man', 'Spider-Man', 'Thor') > movies <- c('Iron Man', 'The Avengers', 'Spider-Man', 'Thor') > releaseyear <- c(2008, 2010, 2002, 2011) |
Think you know the answer? Click here, and find out if you are right. We keep track of your score to give you bragging rights against your peers. This question is worth 1 point in this category: R Language. We'd love to give you credit for your own question and answer. To submit a QOTD, simply log in to the Contribution Center. |
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| Yesterday's Question of the Day |
| Yesterday's Question (by Steve Jones): What does this code do? DECLARE @d1 DATETIME = '20170101 09:42' DECLARE @d2 DATETIME = '20170301 22:22' SELECT DATEADD(DAY, DATEDIFF(DAY, @d2, @d1), @d2) Answer: Returns the date from @d1 and the time from @d2 Explanation: This codce will find the difference between the dates, which is -59 days (DATEDIFF(DAY, @d2, @d1)). This is added to the @d2, which brings the date of @d2 back to @d1, with the same time. Ref: Datediff - click here Dateadd - click here » Discuss this question and answer on the forums |
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